DOFMaster
for Windows® operating systems DOFMaster LE for Palm OS® platform On-line Depth of Field Calculator On-line Depth of Field Table Hyperfocal Distance Chart DOFMaster for iPhone / iPod Touch DOFMaster for Android Steam Tables for iPhone / iPod Touch Articles FAQ Recommended Books Support Contact Links Engineering Software Home |
millimeters; however, the result will also be in millimeters. At this point, you must convert millimeters A = FGIinches x 12 feetA =inchesI = 305mm x 10 ftmm x .04 (conversion factor) = 4 inchesphotograph an object 10 feet high from a distance of 30 feet. What is the length of the image? The formula and computations are as follows: F =IAGF = 4 x 20I = F GAI =24 x 10I = 24 inches x 10 feetfeetrequested to make a 9-inch photograph of a board 12 maximum distance from that wall to the opposite side photograph using an 8x10 camera equipped with a G = IAFG = 9 inches x 16 feetinchesinches). The unknown factor is the necessary lens-to-subject distance required to make the photograph using this camera. The formula and computations are as follows: required lens-to-subject distance is only 16 feet. This allows the photographer 4 feet (20 - 16 = 4) in which to set up and operate the camera. feet high at a distance of 20 feet is focused on the film plane. What is the lens focal length? camera equipped with a 12-inch focal-length lens to obtain a 9-inch image from a distance of 16 feet, you can photograph an object of what maximum length? To solve this problem, you should have the formula and computation as follows: of 9 inches from a distance of 16 feet, is 12 feet. Using Various Lensesyour range of lenses to become a more versatile photographer. Basic Photography Course Privacy Policy |